Asked by Anonymous
if f'(x)=3x^2-2x+1 and the graph of f(x) contains the point (2,2). find f(x).
Please help I know I need to use integration
Please help I know I need to use integration
Answers
Answered by
Reiny
integrating f ' (x), we get
f(x) = x^3 - x^2 + x + c, where c is a constant
but the point (2,2) lies on f(x) , so
2 = 8 - 4 + 2 + c
c = -4
f(x) = ...
f(x) = x^3 - x^2 + x + c, where c is a constant
but the point (2,2) lies on f(x) , so
2 = 8 - 4 + 2 + c
c = -4
f(x) = ...
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