The surface acceleration of gravity is proportional to M/R^2.
On the star surface, g will be higher by a factor 1000/(1/5)^2 = 25000.
So, multiply the weight on Earth by that factor
an imaginary dense star Z has 1/5 the radius of earth, but 1000 times earth's mass. How much would a masss weighing 1.0 N on earth weigh on Star z
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