Asked by Joanna Luz
pls help me solve this problem..
charges of +2.0, 3.0 and -8.0µC are placed at the vertices of an equilateral triangle of a side 10 cm. Calculate the magnitude of the force acting on the -8µC charge due to the other two charges.
charges of +2.0, 3.0 and -8.0µC are placed at the vertices of an equilateral triangle of a side 10 cm. Calculate the magnitude of the force acting on the -8µC charge due to the other two charges.
Answers
Answered by
drwls
Add the vector sum of
-k*2*8*10^-12/0.1^2 and
-k*3*8*10^-12/0.1^2,
applied 60 degrees apart.
k is the Coulomb constant,
8.99*10^9 N/m^2*C^2
There will be an attraction force in a direction between the two other points of the triangle. It will not bisect the angle, because the forces are unequal.
-k*2*8*10^-12/0.1^2 and
-k*3*8*10^-12/0.1^2,
applied 60 degrees apart.
k is the Coulomb constant,
8.99*10^9 N/m^2*C^2
There will be an attraction force in a direction between the two other points of the triangle. It will not bisect the angle, because the forces are unequal.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.