Asked by Anonymous
. (square rt. 5) +(square rt. 25) =
2. If y=x^2 +2x +k passes through the point (1,2), then k =
3. If F(x) = 1 +3x^2, where X cannot be 0, then F(x+2)-F(2)/(x) =
2. If y=x^2 +2x +k passes through the point (1,2), then k =
3. If F(x) = 1 +3x^2, where X cannot be 0, then F(x+2)-F(2)/(x) =
Answers
Answered by
Reiny
1.
√5 + √25 = √5 + 5
2.
sub in the point (1,2)
2 = 1^2 + 2(1) + k
solve for k
3.
I have a strong feeling that you meant:
(F(x+2)-F(2))/(x)
= (1 + 3(x+2)^2 - 25)/x
= (1 + 3x^2 + 12x + 12 - 13)/x
= (3x^2 + 12x)/x = 3x + 12 , x ≠ 0
check my arithmetic
√5 + √25 = √5 + 5
2.
sub in the point (1,2)
2 = 1^2 + 2(1) + k
solve for k
3.
I have a strong feeling that you meant:
(F(x+2)-F(2))/(x)
= (1 + 3(x+2)^2 - 25)/x
= (1 + 3x^2 + 12x + 12 - 13)/x
= (3x^2 + 12x)/x = 3x + 12 , x ≠ 0
check my arithmetic
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