Asked by David
An airplane must reach a speed of 185 mi/h to take off. If the runway is 467 m long, what is the minimum value of the acceleration that will allow the airplane to take off successfully? m/s2
I have been trying the formula vf^2=Vi^2+2AD and solving for A
SO my work has been
185^2=0^2+2A(467)
34225/934=A
36.643=A
I'm assuming my mistake is using speed as Vf but not sure how else to do it. TIA
I have been trying the formula vf^2=Vi^2+2AD and solving for A
SO my work has been
185^2=0^2+2A(467)
34225/934=A
36.643=A
I'm assuming my mistake is using speed as Vf but not sure how else to do it. TIA
Answers
Answered by
Quidditch
Be careful of units.
You expressed the runway length in m (meters), but the takeoff speed is expressed in mi/h (miles/hour). You will need to do some units conversion.
You expressed the runway length in m (meters), but the takeoff speed is expressed in mi/h (miles/hour). You will need to do some units conversion.
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