Asked by Olivia Seth
What is the maximum mass of S8 that can be produced by combining 80g of each reactant?
8SO2 + 16H2S --> 3S8 + 16H2O
i calculated the mass of the reactants
3S8 = 24x 32.066= 769.584 g/mol
16H2 = 32X 1.008= 32.256 g/mol
O= 16X 15.994= 255.904 g/mol
but from there i don't know where to go
8SO2 + 16H2S --> 3S8 + 16H2O
i calculated the mass of the reactants
3S8 = 24x 32.066= 769.584 g/mol
16H2 = 32X 1.008= 32.256 g/mol
O= 16X 15.994= 255.904 g/mol
but from there i don't know where to go