What is the maximum mass of product that can be formed when 76.0 g of solid zinc and 17.5 g nitrogen gas react?
4 answers
i like you to answer my guestion
This is a limiting reagent problem.
1. Write and balance the equation.
3Zn + N2 ==> Zn3N2
2. Convert 76 g Zn to moles. moles = grams/molar mass
3. Convert 17.5 g N2 gas to moles.
4a. Using the coefficients in the balanced equation, convert moles Zn to moles of the product.
4b. Same procedure, convert moles N2 to moles of the product.
4c. Likely the answers to 4a and 4b will not be the same. One must be incorrect. The correct one is ALWAYS the smaller value.
5. Using the value from 4c, convert moles Zn3N2 to grams.
grams = moles x molar mass.
1. Write and balance the equation.
3Zn + N2 ==> Zn3N2
2. Convert 76 g Zn to moles. moles = grams/molar mass
3. Convert 17.5 g N2 gas to moles.
4a. Using the coefficients in the balanced equation, convert moles Zn to moles of the product.
4b. Same procedure, convert moles N2 to moles of the product.
4c. Likely the answers to 4a and 4b will not be the same. One must be incorrect. The correct one is ALWAYS the smaller value.
5. Using the value from 4c, convert moles Zn3N2 to grams.
grams = moles x molar mass.
Okay thanks. I worked it out and got the correct answer of 86.8 grams for the mass product.
This is a typical limiting reagent problem You can take this procedure and apply it to the earlier problem you had.