Asked by Bob
The distance between the points (14,-18) and (15,-8) is?
The point (a,b) is such that (14,-18) is the midpoint of the segment from (15,-8) to (a,b). Then a and =?
The point (a,b) is such that (14,-18) is the midpoint of the segment from (15,-8) to (a,b). Then a and =?
Answers
Answered by
Damon
average x = 14 = (15 + a)/2
28 = 15 + a
a = 13
average y = -18 = (-8 +b)/2
-36 = -8 + b
b = -28
so
(13,-28)
28 = 15 + a
a = 13
average y = -18 = (-8 +b)/2
-36 = -8 + b
b = -28
so
(13,-28)
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