Asked by Anonymous
Calculate the maximum height using the initial speed, half-time, and angle. The initial speeed is 18m/s, half time is 1.8, and the angle is 75. And how is this written out to solve.
Answers
Answered by
drwls
Max height H is given by
2gH = (Vo sin A)^2
You don't need the half-time, T, if you know g.
Vo sin A = g T
g = Vo sinA /T
2 Vo sin A*H/T = (Vo sin A)^2
H = Vo sinA*T/2
in other words, the average vertical velocity component multiplied by the half-time.
2gH = (Vo sin A)^2
You don't need the half-time, T, if you know g.
Vo sin A = g T
g = Vo sinA /T
2 Vo sin A*H/T = (Vo sin A)^2
H = Vo sinA*T/2
in other words, the average vertical velocity component multiplied by the half-time.
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