Asked by iloegbunam kamsy
Calculate the maximum height a ball of mass 1.2 kilograms will attend if projected vertically upwards with an initial velocity of 17 m/s
Answers
Answered by
R_scott
time to peak (t) ... 17 m/s / 9.8 m/s^2
average velocity during ascent ... (17 m/s + 0 m/s) / 2
max height = (time to peak) * (average ascent velocity)
average velocity during ascent ... (17 m/s + 0 m/s) / 2
max height = (time to peak) * (average ascent velocity)
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