Question
Two bullets have masses of 4.6 g and 11 g,
respectively. Each is fired with a speed of 41.0
m/s.
a) What is the kinetic energy of the first
bullet?
Answer in units of J.
respectively. Each is fired with a speed of 41.0
m/s.
a) What is the kinetic energy of the first
bullet?
Answer in units of J.
Answers
drwls
a) Kinetic Energy = (1/2)*M1*V^2
M1 = 0.0046 kg
Information about the second bullet is not needed to answer this question.
M1 = 0.0046 kg
Information about the second bullet is not needed to answer this question.
Graham
KE= 0.0046 x 41 x 41 x 0.5
= 3.8663 Joules
= 3.8663 Joules