Question
Two 4.6 g bullets are fired with speeds of 36.9
m/s and 74.8 m/s, respectively.
a) What is the kinetic energy of the first
bullet?
Answer in units of J.
b) What is the kinetic energy of the second
bullet?
Answer in units of J.
I got part A), which is 3.131703J but i cant get part B.
m/s and 74.8 m/s, respectively.
a) What is the kinetic energy of the first
bullet?
Answer in units of J.
b) What is the kinetic energy of the second
bullet?
Answer in units of J.
I got part A), which is 3.131703J but i cant get part B.
Answers
Henry
Mass = 4.6g/1000 = 0.0046 kg
a. KE1 = 0.5*M*V1^2 = 3.13 J.
b. KE@ = 0.0023*74.8^2 = 12.87 J.
a. KE1 = 0.5*M*V1^2 = 3.13 J.
b. KE@ = 0.0023*74.8^2 = 12.87 J.