Asked by anon
Solve the equation
(u-1)^2=2u^2-3u-29
for u .
(u-1)^2=2u^2-3u-29
for u .
Answers
Answered by
helper
This was answered the first time you posted it. I pasted the answer below.
(u - 1)^2 = 2u^2 - 3u - 29
u^2 - 2u + 1 = 2u^2 - 3u - 29
u^2 - u - 30 = 0
This does not factor.
Solve by using the quadratic formula or the method of completing the square.
Post your answer and someone will check it for you.
(u - 1)^2 = 2u^2 - 3u - 29
u^2 - 2u + 1 = 2u^2 - 3u - 29
u^2 - u - 30 = 0
This does not factor.
Solve by using the quadratic formula or the method of completing the square.
Post your answer and someone will check it for you.
Answered by
anon
I got 1 +or- the sqrt 90/2
Answered by
helper
u^2 - u - 30 = 0
Using the quadratic formula,
x =(-b +- (sqrt(b^2 - 4ac))/2a
a = 1, b = -1, c = -30
x = 1 +- (sqrt(-1^2 - 4(1)(-30))/2
x = (1 +- (sqrt(1 + 120))/2
x = (1 +- (sqrt(121))/2
x = (1 +- 11)/2
x = (1 + 11)/2 = 6
x = (1 - 11)/2 = -5
Using the quadratic formula,
x =(-b +- (sqrt(b^2 - 4ac))/2a
a = 1, b = -1, c = -30
x = 1 +- (sqrt(-1^2 - 4(1)(-30))/2
x = (1 +- (sqrt(1 + 120))/2
x = (1 +- (sqrt(121))/2
x = (1 +- 11)/2
x = (1 + 11)/2 = 6
x = (1 - 11)/2 = -5
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