Asked by mie_y98
anyone explain how this cos 2A cos A – sin 2A sin A
can become to this
cos (2A + A) = cos 3A
can become to this
cos (2A + A) = cos 3A
Answers
Answered by
Reiny
look at the definition of
cos(A+B)
cosAcosB - sinAsinB = cos(A+B)
now compare that to the given
cos2AcosA - sin2AsinA
you will reach the "inescapable" conclusion that it must be
cos(2A+A) or cos 3A
If you want the proof of why the identity is true ....
here is one by Khan
http://khanexercises.appspot.com/video/proof--cos-a-b-----cos-a--cos-b---sin-a--sin-b?playlist=Trigonometry
cos(A+B)
cosAcosB - sinAsinB = cos(A+B)
now compare that to the given
cos2AcosA - sin2AsinA
you will reach the "inescapable" conclusion that it must be
cos(2A+A) or cos 3A
If you want the proof of why the identity is true ....
here is one by Khan
http://khanexercises.appspot.com/video/proof--cos-a-b-----cos-a--cos-b---sin-a--sin-b?playlist=Trigonometry
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