Asked by ash
Someone attaches a 27 kg bale of hay to one end of a rope passing over a frictionless pulley connected to a beam in a hay barn. Someone else pull down on the opposite en of the rope with a force of 397 N. Ignoring the mass of the rope, what will be the magnitude and directionf the bales acceleration if the gravitational force is 265 N?
Answers
Answered by
drwls
Just use F = M*a, where:
M = bale mass = 27 kg,
F = net force = T - Weight
T = pulling force, which will be the tension on either side of the pulley.
Weight = M g = 265 N
a = F/M = (397-265)/27 = 4.9 m/s^2
M = bale mass = 27 kg,
F = net force = T - Weight
T = pulling force, which will be the tension on either side of the pulley.
Weight = M g = 265 N
a = F/M = (397-265)/27 = 4.9 m/s^2
Answered by
ash
Ok, that's what I got but I wasn't sure if it was correct. Thanks so much!
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