Asked by Anonymous
A tightrope walker attaches a cable to the roofs of two adjacent buildings. The cable is 23.5 m long. The angle of inclination of the cable is 13 degrees. The shorter building is 12.0 m high. What is the height of the taller building to the nearest tenth of a metre?
I tried drawing it but it didn't work. I don't which sides to label please help :(
I tried drawing it but it didn't work. I don't which sides to label please help :(
Answers
Answered by
Reiny
the diagram looks rather routine
draw the smaller building and mark is as 12 m high
draw the other building a bit taller .
draw a horizontal from the smaller to the taller, label the difference in height as x
draw in your cable,
Don't you have a right-angled triangle with a base angle of 13°, opposite as x and hypotenuse as 23.5 M ?
so sin 13° = x/23.5
x = 23.5sin13
= 5.2863..
= 5 m to the nearest metre
So the height of the taller building is 12 + 5 or 17 metres.
draw the smaller building and mark is as 12 m high
draw the other building a bit taller .
draw a horizontal from the smaller to the taller, label the difference in height as x
draw in your cable,
Don't you have a right-angled triangle with a base angle of 13°, opposite as x and hypotenuse as 23.5 M ?
so sin 13° = x/23.5
x = 23.5sin13
= 5.2863..
= 5 m to the nearest metre
So the height of the taller building is 12 + 5 or 17 metres.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.