Ammonia gas can be prepared by the reaction CaO(s) + 2NH4Cl(s) - 2NH3(g) + H2O(g) + CaCl2(s) If 112 g CaO reacts with 224 g NH4Cl, how many moles of reactants and products are there when the reaction is complete?

Question

Ammonia gas can be prepared by the reaction CaO(s) + 2NH4Cl(s) -> 2NH3(g) + H2O(g) + CaCl2(s) If 112 g CaO reacts with 224 g NH4Cl, how many moles of reactants and products are there when the reaction is complete?

DrBob222 · Answer

This is a limiting reagent problem. How do I know that? Because BOTH reactants are given. This problem follows the exact process I outlined in the Cu/H2SO4 problem above. Just follow those steps. Post your work if you get stuck.