Asked by Maria

Ammonia gas can be prepared by the reaction CaO(s) + 2NH4Cl(s) -> 2NH3(g) + H2O(g) + CaCl2(s)
If 112 g CaO reacts with 224 g NH4Cl, how many moles of reactants and products are there when the reaction is complete?

Answers

Answered by Linda
quantity (g) of pure CaCl2 in 7.5g of CaCl2 9H2O
Answered by Susmita
This answer is right
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