Question

determine the point of intersection

y=logbase 10(x-2)

and y=1-logbase 10(x+1)

Answer 1

solve for first x

10^y=(x-2)
x= 10^y +2
solve for the second x
y-1=log(x+1)
10^(y-1)=x+1 or x= 10^(y-1) +1

the x=x, y=y

10^(y-1)+1=10^y +2
remember a^(b-c)= a^b/a^c so

10^y/10 + 1=10^y +2

10^y (-9/10)=1
or -9*10^y=10
log of each side
-9 +y=1
y=10
so, now figure x..
x= 10^(y-1) +1=10^9+1

weird. Check my work.

Answer 2

you are THE BESTT!!

Answer 3

its wrong

you wrote
10^(y-1)+1=10^y +2

its supposed to be

10^(y-1)-1=10^y +2


THE ANSWER IS APPARENTLY 2, log base 10 2