Asked by Britt
Find the limit. Use L'Hopitals Rule if necessary.
lim (x^2+3x+2)/(x^2+x)
x -> 0
lim (x^2+3x+2)/(x^2+x)
x -> 0
Answers
Answered by
Reiny
lim (x^2+3x+2)/(x^2+x)
x -> 0
= lim (x+2)/x
x -> 0
which is undefined
so there is no limit
x -> 0
= lim (x+2)/x
x -> 0
which is undefined
so there is no limit
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