Asked by Ryan
A bug walks along the circle x^2 + y^2 = 4. When it is at the point (1, (3)^1/2)), dx/dt = 2. Find dy/dt at this instant.
Answers
Answered by
Reiny
2x dx/dt + 2y dy/dt = 0
dy/dt = -x dx/dt/y
= -1(2)/√3
= -2/√3
dy/dt = -x dx/dt/y
= -1(2)/√3
= -2/√3
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