Asked by Zukii
solve the following:
2^-x=3^2x+2
2^-x=3^2x+2
Answers
Answered by
helper
If this is your problem
2^-x = 3^(2x+2)
take logarithms of both sides
-x log 2 = (2x + 2)log 3
-x log 2 = 2x log 3 + 2 log 3
-x log 2 - 2x log 3 = 2 log 3
x (-log 2 - 2 log 3) = 2 log 3
x = -(2 log 3)/(log 2 + 2 log 3)
plug in log values
x = -0.760188
2^-x = 3^(2x+2)
take logarithms of both sides
-x log 2 = (2x + 2)log 3
-x log 2 = 2x log 3 + 2 log 3
-x log 2 - 2x log 3 = 2 log 3
x (-log 2 - 2 log 3) = 2 log 3
x = -(2 log 3)/(log 2 + 2 log 3)
plug in log values
x = -0.760188
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