Asked by Rachael
The question is: Hydrogen and oxygen gas combine explosively to produce water. Write a balanced chemical equation for this process. If 10 mol of hydrogen reacted with oxygen, what volume of liquid water could be produced?
Is this right for the balanced equation? 4H + O₂ → 2H₂O
Does the mole stay the same? Does 10 mol of hydrogen that has reacted with oxygen remain as 10 mol?
How do I go about working out the volume of water now?
Thank you.
Is this right for the balanced equation? 4H + O₂ → 2H₂O
Does the mole stay the same? Does 10 mol of hydrogen that has reacted with oxygen remain as 10 mol?
How do I go about working out the volume of water now?
Thank you.
Answers
Answered by
DrBob222
H occurs as a diatomic molecule (as does oxygen) so the equation should be
2H2 + O2 ==> 2H2O
(10 moles H2 will produce 10 moles H2O --ONLY IF there is sufficient oxygen present and that will be 5 moles oxygen needed for 10 moles H2). 1 mole H2O has a molar mass of 18 grams; therefore, 10 moles will have a mass of 180 grams. If the density of water is 1.00 g/mL, that will be 180 mL water. Check my thinking.
2H2 + O2 ==> 2H2O
(10 moles H2 will produce 10 moles H2O --ONLY IF there is sufficient oxygen present and that will be 5 moles oxygen needed for 10 moles H2). 1 mole H2O has a molar mass of 18 grams; therefore, 10 moles will have a mass of 180 grams. If the density of water is 1.00 g/mL, that will be 180 mL water. Check my thinking.
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