Asked by Anonymous
A hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:
En=-(2.18x10^(-18)J)Z^2(1/(n^2))
where n is the principal quantum number and Z is the atomic number of the element.
Calculate the ionization energy (in kJ/mol) of the He+ ion.
???
En=-(2.18x10^(-18)J)Z^2(1/(n^2))
where n is the principal quantum number and Z is the atomic number of the element.
Calculate the ionization energy (in kJ/mol) of the He+ ion.
???
Answers
Answered by
DrBob222
I think I did this for you last night.
Z = 2^2
n = 1. Punch into the calculator and move on.
Z = 2^2
n = 1. Punch into the calculator and move on.
Answered by
Anonymouse
if you plug in
Z=2^2
n=1
its wrong and i don't knwo why
Z=2^2
n=1
its wrong and i don't knwo why
Answered by
Mandy
It is -8,72 x 10^-21 kJ
Reason: After punching in those values you then have to convert that answer from J to kJ which 1kJ=1000J
Reason: After punching in those values you then have to convert that answer from J to kJ which 1kJ=1000J
Answered by
n
STILL WRONG
Answered by
no
Still figuring it out to this day huh?