Question
a 10 kg gun recoils with a speed of 0.1 meter per second as it fires a 0.001kg bullet. what is the speed of the bullet as it leaves the gun
Answers
bobpursley
Conservation of momentum:
initial momentum=final momentum
0=10kg*(-0.1m/s)+.001kg*deltaV
solve for delta V
initial momentum=final momentum
0=10kg*(-0.1m/s)+.001kg*deltaV
solve for delta V
Anonymous
10.20