Asked by Diana
                a 10 kg gun recoils with a speed of 0.1 meter per second as it fires a 0.001kg bullet. what is the speed of the bullet as it leaves the gun
            
            
        Answers
                    Answered by
            bobpursley
            
    Conservation of momentum:
initial momentum=final momentum
0=10kg*(-0.1m/s)+.001kg*deltaV
solve for delta V
    
initial momentum=final momentum
0=10kg*(-0.1m/s)+.001kg*deltaV
solve for delta V
                    Answered by
            Anonymous
            
    10.20
    
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