Asked by alli
A catcher's mitt recoils a distance of 0.177 m in bringing a 0.176 kg baseball to a stop. If the applied force is 504 N, then what was the speed of the baseball at the moment of contact with the catcher's mitt?
Answers
Answered by
Henry2
Work = F*d = 504 * 0.177 = 89.2 J.
Work = Change in kinetic energy:
Work = 0.5M*V^2 = 89.2,
0.5*0.176V^2 = 89.2,
V =
Work = Change in kinetic energy:
Work = 0.5M*V^2 = 89.2,
0.5*0.176V^2 = 89.2,
V =
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