if log(x+1) 27=3 find the value of x

*(x+1) is the base

i know that the answer is 2 but i have no clue how to get that

2 answers

log(x+1) 27=3

since,
logb N = x
b^x = N

this can be written as
(x + 1)^3 = 27
take cube root of each side
x + 1 = 3
x = 2
Thanks
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