Asked by Matthew
The activity of a sample of a radioactive isotope is 1800Bq. If this isotope has a half-life of 16 days, what is the activity after 16 days?, 24 days?, and 60 days?
Answers
Answered by
drwls
Radioactivity is half as much (900 Bq) after 16 days. For other times t (in days), use the equation
Activity = 1800 * (1/2)^(t/16)
t/16 is an exponent.
Activity = 1800 * (1/2)^(t/16)
t/16 is an exponent.
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