Question

A cat chases a mouse across a 1.7 m high
table. The mouse steps out of the way, and
the cat slides off the table and strikes the floor
2.1 m from the edge of the table.
The acceleration of gravity is 9.81 m/s2 .
What was the cat’s speed when it slid off
the table?
Answer in units of m/s.

Answer 1

The time to fall H = 1.7 m, when there is zero initial vertical velocity component, is
t = sqrt(2H/g) = 0.589 s

The cat's speed when sliding off is
Vx = 2.1 m/0.589 s = 3.57 m/s,

since the cat's horizontal velocity component, Vx, remains constant during the fall.

Answer 2

sdfsdfsdf

Answer 3

guys its literally 0.978 m/s duh

Answer 4

A cat chases a mouse across a 1.7 m high
table. The mouse steps out of the way, and
the cat slides off the table and strikes the floor
2.8 m from the edge of the table.
The acceleration of gravity is 9.81 m/s
2
.
What was the cat’s speed when it slid off
the table?
Answer in units of m/s.