Question

A cat chases a mouse, which has a 160 meters head start.For every 7 metes the mouse runs, the cat run 9 meters. How far must the car run to catch the mouse

Answer 1

Please I need solutions

Answer 2

both run for time t
cat runs d + 160 meters
cat speed= v
mouse speed = 7/9 v
so
7/9 v * t = d
v * t = d+160

t = 9 d / 7 v
v (9 d/7v) = d + 160
9d / 7 = d + 160
9 d= 7 d + 1120
2 d = 1120
d = 560
so
d + 160 = 720 = cat distance

Answer 3

for every 9 m the cat runs , he closes the distance to the mouse by 2 m

160 m / 2 m = 80 ... "steps" to catch mouse

9 m * 80 = ?

Answer 4

LOL --- Thanks R_scott. That is much easier than my way.

Answer 5

160/2 = answer because the cat is running 2 more meters that the mouse at a time