Asked by Vilika
if 150g of Ca(OH)2 is reacted with excess H2, how much energy will be needed?
Answers
Answered by
DrBob222
Write and balance the equation. It should look something like this.
Ca(OH)2 + H2 ==> CaH2 + H2O You balance.
Delta Hrxn = (n*delta H products)-(n*delta H reactants)
Ca(OH)2 + H2 ==> CaH2 + H2O You balance.
Delta Hrxn = (n*delta H products)-(n*delta H reactants)
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