Asked by fiyin
150g of ice at 0'c is mixed with 300g of water at 50'c. calculate the temperature of a mixture
Answers
Answered by
bobpursley
sum heats transfered is zero (some are + gains, some are - gains).
heat to melt ice+heat to heat melted ice + heat to original water=0
Lf=latent heat of fusion ice
cw=specific heat capacity of water
Lf*150+150*cw(Tf-0)+300*cw*(Tf-50)=0
look up Lf
solve for Tf
heat to melt ice+heat to heat melted ice + heat to original water=0
Lf=latent heat of fusion ice
cw=specific heat capacity of water
Lf*150+150*cw(Tf-0)+300*cw*(Tf-50)=0
look up Lf
solve for Tf
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