Asked by Christine
A block weighing 6.8 N requires a force of
2.5 N to push it along at constant velocity.
What is the coefficient of friction for the
surface?
A weight W is now placed on the block and
4.6 N is needed to push them both at constant
velocity.
What is the weight W of
Answers
Answered by
drwls
2.5 N = (weight) x (kinetic friction coefficient)
Solve for the kinetic friction coefficient.
In part 2, the total weight being pushed increased by a factor 4.6/2.5 = 1.84
The total weight being pushed must therefore have increased by the same factor, to 12.5 N.
The added weight must have been 12.5 - 6.8 = __ N
Solve for the kinetic friction coefficient.
In part 2, the total weight being pushed increased by a factor 4.6/2.5 = 1.84
The total weight being pushed must therefore have increased by the same factor, to 12.5 N.
The added weight must have been 12.5 - 6.8 = __ N
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.