Asked by Chris
A player strikes a hockey puck giving it a velocity of 47.673 m/s. The puck slides across the ice for 0.175 s after which time its velocity is 46.473 m/s.
The acceleration of gravity is 9.8 m/s2 . If the puck strikes the goalie’s pads and stops in a distance of 4.39 cm, what average force is exerted on the pads?
Answer in units of N.
The acceleration of gravity is 9.8 m/s2 . If the puck strikes the goalie’s pads and stops in a distance of 4.39 cm, what average force is exerted on the pads?
Answer in units of N.
Answers
Answered by
Damon
Sorry, I am not interested in the original speed or gravity or how long it slid across the ice.
However I do need the mass of the puck.
F = m *(change in velocity)/time
time = distance/average speed stopping
distance = .0439m
average speed stopping = 23.236 m/s
time = .0439/23.236 seconds to stop
F = m (46.473) (23.236/.0439)
so if I only knew m, I could help you.
However as you can sense, the heavier the puck, the more the force.
However I do need the mass of the puck.
F = m *(change in velocity)/time
time = distance/average speed stopping
distance = .0439m
average speed stopping = 23.236 m/s
time = .0439/23.236 seconds to stop
F = m (46.473) (23.236/.0439)
so if I only knew m, I could help you.
However as you can sense, the heavier the puck, the more the force.
Answered by
Chris
The mass of the hockey puck is 185 grams. When you said time = distance/average speed stopping, in the equation F = m (46.473)*(23.236/.0439), did you mean this, .0439/23.236.