Asked by Jessie
How do I simply 4^-1x^0/y^-1
possible answers:
1/4y
4y
y/4
4
I really don't get these- but I think it might be y/4 because you take the negative to the top and the negative to the bottom, right?
possible answers:
1/4y
4y
y/4
4
I really don't get these- but I think it might be y/4 because you take the negative to the top and the negative to the bottom, right?
Answers
Answered by
Reiny
remember that x^(-a) = 1/x^a
and a^0 - 1 for all a>0
4^-1x^0/y^-1
= (1/4)(x^0)(1/y)
= (1/4)(1)(1/y)
= 1/(4y)
(they should not have written the answer as 1/4y , it would mean (1/4) y )
and a^0 - 1 for all a>0
4^-1x^0/y^-1
= (1/4)(x^0)(1/y)
= (1/4)(1)(1/y)
= 1/(4y)
(they should not have written the answer as 1/4y , it would mean (1/4) y )
Answered by
Jessie
The way you explained it, I can understand it-the way my teacher explained it-I was still confused
Thank you very much
Thank you very much
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