Question
what is the value of the discriminant x^2-9
Answers
b^2 = 0
-4ac = -4(1)(-9) = 36
b^2-4ac = 36
note
sqrt (36) is 6
-4ac = -4(1)(-9) = 36
b^2-4ac = 36
note
sqrt (36) is 6
Small correction Damon:
the formula is
(-b + sqrt(b^2 - 4ac)) / 2a
-
Ans : + sqrt(36) / 2
-
ie + 6/2 and -6/3
Ans : + 3 and -3
Easier way: Method II
X^2 -9 = 0
X^2 = 9
X = Sqrt(9)
X = 3 or -3
Done!
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