Question

Find an algebraic expression for f'

f(x)= 2e^x+ pi
f(x)=e^5-4e^x
f(x)=e^x+x^e+e
f(x)= e^pi +pi^x+ x^pi

I didn't understand these at all

Answer 1

2 e^x

-4 e^x because e^5 is a constant

e^x + e x^(e-1) because e is constant

pi^x ln pi + pi x^(pi-1) because e^pi is constant