Question
the side of a cube is expanding at a constant rate of 2 centimeters per sesond. what is the instantaneous rate of change of the surface area of the cube, in cm2 per second, when its volume is 27 cubic cm
Answers
Marth
For a cube, SA = 6s^2. Differentiate with respect to time.
dSA/dt = 12s(ds/dt)
ds/dt is given as 2cm/s.
When V = 27cm^3, s = 3cm. dSA/dt=?
dSA/dt = 12s(ds/dt)
ds/dt is given as 2cm/s.
When V = 27cm^3, s = 3cm. dSA/dt=?
GEORGE
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