Asked by Felicia

the side of a cube is expanding at a constant rate of 2 centimeters per sesond. what is the instantaneous rate of change of the surface area of the cube, in cm2 per second, when its volume is 27 cubic cm

Answers

Answered by Marth
For a cube, SA = 6s^2. Differentiate with respect to time.

dSA/dt = 12s(ds/dt)

ds/dt is given as 2cm/s.
When V = 27cm^3, s = 3cm. dSA/dt=?
Answered by GEORGE
72
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