Asked by Emily
im helping my brother with his homework but i completely forgot how to do this?
Solve the system by substitution:
y=3x-4
x+5y=-4
Solve the system by substitution:
y=3x-4
x+5y=-4
Answers
Answered by
Bosnian
x+5y=-4
y=3x-4
x+5*(3x-4)=-4
x+15x-20=-4
16x=-4+20
16x=16 Divide wth 16
x=1
y=3x-4
y=3*1-4
y=3-4=-1
x=1 y=-1
Cheking of result:
y=3x-4
-1=3*1-4
-1=3-4
-1=-1
x+5y=-4
1+5*(-1)=-4
1-5=-4
-4=-4
y=3x-4
x+5*(3x-4)=-4
x+15x-20=-4
16x=-4+20
16x=16 Divide wth 16
x=1
y=3x-4
y=3*1-4
y=3-4=-1
x=1 y=-1
Cheking of result:
y=3x-4
-1=3*1-4
-1=3-4
-1=-1
x+5y=-4
1+5*(-1)=-4
1-5=-4
-4=-4
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