Asked by Akkam
Calcium chloride, CaCl2, has been used to melt ice from roadways. Given that a solution is 25% CaCl2 by mass, estimate the freezing point.
Answers
Answered by
bobpursley
notice you get three ions per formula.
deltatemp=3*(-1.8)molality
now, molality: moles/kg solvent.
assume .75 kg solvent, then mass of solute must be 250grams, to give a twenty-five percent.
molesCaCl2=250/110 about figure it out.
molality=about 2.4/.75 you need to do this accurately.
deltatemp=3*(-1.8)molality
now, molality: moles/kg solvent.
assume .75 kg solvent, then mass of solute must be 250grams, to give a twenty-five percent.
molesCaCl2=250/110 about figure it out.
molality=about 2.4/.75 you need to do this accurately.
Answered by
Nagaa
CaCl2 = have 3 ions
delta temp = 3*(-1.858)molality = -5.57 x molality
molality = moles solute/kg solvent.
assume 0.75 kg solvent, then mass of solute must be 250 grams, to give a 25 %.
moles CaCl2 = 250/110 = 2.27 mol
molality = 2.27 mol / 0.75 kg = 3.03 m
Delta Temp = 3*(-1.858)*3.03 = -16.9 C
Thanks Bobpursley
delta temp = 3*(-1.858)molality = -5.57 x molality
molality = moles solute/kg solvent.
assume 0.75 kg solvent, then mass of solute must be 250 grams, to give a 25 %.
moles CaCl2 = 250/110 = 2.27 mol
molality = 2.27 mol / 0.75 kg = 3.03 m
Delta Temp = 3*(-1.858)*3.03 = -16.9 C
Thanks Bobpursley
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