Asked by John Jones

When 3.00g of calcium chloride were reacted in an excess of silver nitrate, 6.4g of AlCl
were produced. What was the percent yield in this reaction?
Answered by heyo ❄
is this from a CA lesson?
Answered by oobleck
CaCl2 + 2AgNO3 → 2AgCl + Ca(NO3)2
3.00g CaCl2 is 0.027 moles
So you expect 0.054 moles of AgCl
6.4g AgCl is 0.0446 moles
so the yield is 0.446/0.054 = 82.7%
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