Asked by john

Find the average value of f (x)= √(4x +1) over the interval 0 ≤ x ≤ 2.
Answered by Damon
(1/2) int (4x+1)^.5 dx from 0 to 2

(1/2) [(2/(3*4))(4x+1)^1.5] at 2 - at 1

(1/12) [ (27) - (11.2) ]

1.32