While travelling a distance of 27m the velocity of a train increased from 12m/sec to 54km/hr what is the uniform acceleration of the train.

2 answers

54 km/hr = 15 m/s

Vfinal^2 - Vinitial^2 = 2 a X
81 m^2/s^2 = 2*a*27m
Solve for acceleration, a.
1,5