Asked by Jessica
                THANK YOU!
Solve by substitution
3x+6y=6;
-6x+y=40
My WORK: Y=40+6X;
3X+6(40+6X)=6; 3X+240+36X=6;
x=-5.51;
y=40+6(-5.51); y=40+-33.06;
y=6.94
(-5.51,6.94)
Is this right???
            
        Solve by substitution
3x+6y=6;
-6x+y=40
My WORK: Y=40+6X;
3X+6(40+6X)=6; 3X+240+36X=6;
x=-5.51;
y=40+6(-5.51); y=40+-33.06;
y=6.94
(-5.51,6.94)
Is this right???
Answers
                    Answered by
            Quidditch
            
    You have and error.
3X + 240 + 36X = 6
39X = -234
X = ?
    
3X + 240 + 36X = 6
39X = -234
X = ?
                    Answered by
            Quidditch
            
    my misspelling...
You have AN eror.
    
You have AN eror.
                    Answered by
            Jessica
            
    OK, I will try this. Please let me know. 
39x= -234; Divide by 39 on each side.
x = 6.
y=40+6(-6); 40+-36 = 4; (6,4)?
    
39x= -234; Divide by 39 on each side.
x = 6.
y=40+6(-6); 40+-36 = 4; (6,4)?
                    Answered by
            MathMate
            
    "39x= -234; Divide by 39 on each side.
x = <b>-</b>6. "
    
x = <b>-</b>6. "
                    Answered by
            Jessica
            
    thank you so much!
    
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