Asked by Pedro
For a model rocket, the altitude h in meters, as a function of time t, in seconds, is given by h=68t-8t^2. after how many seconds will it hit the ground?
Answers
Answered by
MathMate
When it is at ground level, h(t)=0.
So solve for h(t)=0,
h(0)=68t-8t^2
=t(68-8t)=0
t=0 or t=68/8=17/4=4.25
So solve for h(t)=0,
h(0)=68t-8t^2
=t(68-8t)=0
t=0 or t=68/8=17/4=4.25
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