Asked by maria
How much heat must be added to 0.55 kg of aluminum to change it from a solid at 180°C to a liquid at 660°C (its melting point)? The latent heat of fusion for aluminum is 4.0x10^5 J/kg.
I understand the Equation Q=mc times change it T
would that be .55 times 4.0 x 10^5 times (660-180) or im i mising something please help im still haveing some trouble with this problem
I understand the Equation Q=mc times change it T
would that be .55 times 4.0 x 10^5 times (660-180) or im i mising something please help im still haveing some trouble with this problem
Answers
Answered by
Damon
FIRST you must heat the Al from 180 to 660
for that you need the heat capacity of Al, call it Cal, which is in your book.
Q1 = .55 * Cal * (660-180)
THEN you melt it
Q2 = .55 * 4*10^5
period, no temp in that eqn it happens at melting point
Then add Q1+Q2
for that you need the heat capacity of Al, call it Cal, which is in your book.
Q1 = .55 * Cal * (660-180)
THEN you melt it
Q2 = .55 * 4*10^5
period, no temp in that eqn it happens at melting point
Then add Q1+Q2
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