Asked by Bobby

Consider the motion of a projectile. It isfired at t = 0. Its initial speed is 36 m/s and its initial projection angle is 55◦ from the horizontal.
The acceleration of gravity is 9.8 m/s2 . y
x
What is the maximum height, h, of its tra jectory?
Answer in units of m.

Answers

Answered by drwls
Maximum height is achieved when the velocity's vertical component is zero.

36*sin55 - gt = 0

Solve for the time t. Then use

y = 30*sin55* t - (g/2)t^2

to get the maximum altitude h.
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