Asked by Ivy
A 21.18 mL of 0.250 M NaOH is titrated with a H2SO4 solution. The initial
volume of H2SO4 was 13.28 and the final volume of H2SO4 was 28.29 mL when
the solution turned very slightly pink. What is the concentration of NaOH?
volume of H2SO4 was 13.28 and the final volume of H2SO4 was 28.29 mL when
the solution turned very slightly pink. What is the concentration of NaOH?
Answers
Answered by
bobpursley
molesacid=2molesbase
Va*Ma=2*Vb*Mb
(28.29-13.28)mL*Ma=2*21.18mL*.250M
solve for Ma
Va*Ma=2*Vb*Mb
(28.29-13.28)mL*Ma=2*21.18mL*.250M
solve for Ma
Answered by
Ivy
I don't understand what you just wrote
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