Asked by klk
An 90 kg person steps into a car of mass 2600 kg, causing it to sink 2.35 cm on its springs. Assuming no damping, with what frequency will the car and passenger vibrate on the springs?
Answers
Answered by
drwls
The spring constant is
k = (90*9.8N/0.0235 m) = 3.75^10^4 N/m
and the vibration frequency is
w = [1/(2 pi)]*sqrt(k/Mtotal)
Mtotal = 2690 kg
w = ___ s^-1
k = (90*9.8N/0.0235 m) = 3.75^10^4 N/m
and the vibration frequency is
w = [1/(2 pi)]*sqrt(k/Mtotal)
Mtotal = 2690 kg
w = ___ s^-1
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.