Asked by Aimee
A normal distribution has a mean of 80 and a standard deviation of 14. Compute the probability of a value between 75.0 and 90.0.
a) .2022
b) .3595
c) .4017
d) None of the above
a) .2022
b) .3595
c) .4017
d) None of the above
Answers
Answered by
yelloe
x1=75
x2=90
z1=(x1-mean)/standard dev. = -0.35
z2=(x2-mean)/standard dev. = 0.71
then look for the area table from your book, get for the equivalent value from z1 and z2, then get the difference of the two.. 0.7642-0.3632 = 0.401
thus, i assumed its C.
x2=90
z1=(x1-mean)/standard dev. = -0.35
z2=(x2-mean)/standard dev. = 0.71
then look for the area table from your book, get for the equivalent value from z1 and z2, then get the difference of the two.. 0.7642-0.3632 = 0.401
thus, i assumed its C.
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